69.3k views
0 votes
How do you solve 3x+4y=12 and 2x=y-6

User Sandya
by
8.0k points

1 Answer

4 votes

3x +4y =12

2x = y-6 Rewrite this as y = 2x+6

now replace that for y in the first equation

3x + 4(2x+6) = 12

now do all the calculations:

3x + 8x +24 =12

11x + 24 = 12

11x = -12

x = -12/11 = -1 1/11

now substitute -12/11 for x in the 2nd equation and solve

y = 2x+6

y = 2(-1 1/11) +6

y = 42/11 = 3 9/11

User Volker Voecking
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories