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How do you solve 3x+4y=12 and 2x=y-6

User Sandya
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1 Answer

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3x +4y =12

2x = y-6 Rewrite this as y = 2x+6

now replace that for y in the first equation

3x + 4(2x+6) = 12

now do all the calculations:

3x + 8x +24 =12

11x + 24 = 12

11x = -12

x = -12/11 = -1 1/11

now substitute -12/11 for x in the 2nd equation and solve

y = 2x+6

y = 2(-1 1/11) +6

y = 42/11 = 3 9/11

User Volker Voecking
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