Question

Three consecutive even numbers have a sum where one half of the sum is between 84 and 96

Answer 1

86 *2 = 172

172/3 = 57.33

54 + 56 +58 =168

168/2 =84

56 + 58 +60 = 174

174/2 =87

58 +60 +62 = 180

180/2 = 90

60 +62 +64 = 186

186/2 = 93

62 +64+66 = 192

192/2 = 96

there are 3 sets of numbers that fall between 84 & 96

1 set equals 84 and 1 set equals 96

so if you are counting those there are 5 sets