What is the volume of 55 L of gas initially at 500 K and 4.25 atm when conditions change to STP? A. 10.5 L B. 428.1 L C. 584.0 L D. 127.6 L

asked Nov 2, 2018 138k views

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6 votes

(55 L) x (273 K) / (500 K) x (4.25 atm) / (1.00 atm) = 127.6 L

Chenna answered Nov 5, 2018

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2 votes

1.55 L) x (273 K) / (500 K) x (4.25 atm) / (1.00 atm) = 127.6 L
So answer A.

Rebca answered Nov 7, 2018