Question

What is the volume of 55 L of gas initially at 500 K and 4.25 atm when conditions change to STP? A. 10.5 L B. 428.1 L C. 584.0 L D. 127.6 L

Answer 1

(55 L) x (273 K) / (500 K) x (4.25 atm) / (1.00 atm) = 127.6 L

Answer 2

1.55 L) x (273 K) / (500 K) x (4.25 atm) / (1.00 atm) = 127.6 L
So answer A.