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Find the vertex for the equation: y = 3x^2 + 18x + 30 (-3, 3) (-3, -51) (3, 111)
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Oct 20, 2018
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Find the vertex for the equation:
y = 3x^2 + 18x + 30
(-3, 3)
(-3, -51)
(3, 111)
Mathematics
college
Aquaflamingo
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y = 3x^2 + 18x + 30
a = 3, b = 18, c = 30
h = -b/2a = -18 / 6 = -3
k = (4ac – b^2
) / 4
a = (360 - 324)/12 = 36/12 = 3
vertex (h, k) = (-3,3)
answer
(-3, 3)
Palisand
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Oct 20, 2018
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Palisand
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I think (-3, 3 ) !!!!!!!!!!!
Emre Isik
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Oct 25, 2018
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Emre Isik
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