Question

The length of a swimming pool is 4 feet longer than 2 times it's width. If the perimeter of the pool is 128 feet, what is the width of the pool

Answer 1

Let L = the length, and W = the width.

L = 2W ......(1)

(L+2)(W+2) - LW = 100 => 2W+2L+4 = 100 ......(2)

Plug (1) into (2), and solve for L,

3L = 96

L = 32 feet

W = L/2 = 16 feet

Answer: The length of the pool is 32 feet, and the width is 16 feet.

Answer 2

x equals 31. so the width is 62 feet. the length is then 66 feet

to find this, write out all your terms (2x,2x,+4) into an equation (2x+2x+4=128) from there, simplify and solve.

4x+4=128
-4 -4
4x=124
--- ----- <--- division
4 4
x=31

then you multiply 31 by 2 to get the width and add 4 to get the length