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Find f ′(x) for f(x) = cos (3x^3).

User Rockystech
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1 Answer

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\bf f(x)=cos(3x^3)\impliedby chain-rule \\\\\\ \cfrac{df}{dx}=-sin(3x^3)\cdot (3\cdot 3x^(3-1))\implies \cfrac{df}{dx}=-9x^2sin(3x^3)
User Sug
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