Question

Completely lost..... please help?

Answer 1

Question 1:

Straight line equation is given in the form
`y=mx+c`, where:

m = the slope
c = the y-intercept

for this question, we have:
the slope, m = 5
y-intercept = -7

All you have to do is 'plug' these values into the equation


`y = 5x-7`
------------------------------------------------------------------------------------------------

Question 2:

We have:

the slope, m = 10
y-intercept, c = -3

Again, plug these values into the equation, we have:


`y = 10x-3`
----------------------------------------------------------------------------------------------------

Question 3:

Here, we've got two coordinates instead. We don't have the slope, m, but we can work it out from the two coordinates

let (-1, 0) be (x₁, y₁) and (0,1) be (x₂, y₂)
Slope, m =
`(-1-0)/(0-1) = (-1)/(-1)=1`

From the graph, we can read the y-intercept, c = 1

Now we have m =1 and c = 1, the equation is

`y=x+1`

----------------------------------------------------------------------------------------------------------------

Question 4

We have two coordinates (-1, 0) and (0, 5)
Slope, m =
`(-1-0)/(0-5) = (-1)/(-5)= (1)/(5)`
y-intercept, c = 5

Equation:
`y = (1)/(5)x+5`