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(10g^2 +3g-10) + (2g^2+g+7)

User Dannie
by
6.2k points

1 Answer

2 votes
Hey!

Let's write the problem.

\left(10g^2+3g-10\right)+\left(2g^2+g+7\right)
Remove the parenthesis.

=10g^2+3g-10+2g^2+g+7
Add like terms...

3g+g=4g

10g^2+2g^2=12g^2
We would be left with something like this,

=12g^2+4g+7-10
Subtract the numbers.

=12g^2+4g-3
That would be our final answer!

Thanks!
-TetraFish
User Nilesh Verma
by
6.0k points
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