Question

An epidemic has hit Minecole City. Its population is declining 34% every hour. In just 3 hours, there are only 25,143 people left in the city. What was the initial population in the city before the epidemic broke out?

Answer 1

The initial population in the city before the epidemic broke out was 38,157.

Step-by-step explanation:

To find the initial population in the city before the epidemic broke out, we can use the formula:

Initial Population = Final Population / (1 - Rate of Decline)

Given that the population is declining 34% every hour and there are only 25,143 people left in the city after 3 hours, we can calculate the initial population as follows:

Initial Population = 25,143 / (1 - 0.34) = 25,143 / 0.66 = 38,157

Answer 2

The initial population in the city before the epidemic broke out was 87455.

Step-by-step explanation:

The decay formula is:
`A=P(1-r)^t` , where
`P=` Initial amount,
`A=` Final amount,
`r=` rate of decay in decimal form and
`t=` time duration.

Here,
`A=25143,\ \ r=34\%=(34)/(100)=0.34,\ \ t=3\ hours`

Plugging these values into the above formula.....

`25143=P(1-0.34)^3\\ \\ 25143=P(0.66)^3\\ \\ 25143=P(0.287496)\\ \\ P=(25143)/(0.287496)=87455.129...\approx 87455`

So, the initial population in the city before the epidemic broke out was 87455.