Register
Find the center and radius of a circle defined by the equation x^2+yy^2+4x-8y+13=0
46.0k views
2 votes
Find the center and radius of a circle defined by the equation x^2+yy^2+4x-8y+13=0

User Winston
by
7.4k points

1 Answer

3 votes
hello :
x²+y²+4x-8y +13 = 0
(x² +4x) +(y² -8y )+13 = 0
(x²+4x+4) -4 +(y-8y +16) -16 +13 = 0
(x+2)² +(y -4)² = 7
the center is : (-2 , 4) and radius √7
User DpDesignz
by
7.0k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

8.8m questions

11.4m answers

Other Questions

What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement  how thick must the cement be to cover field
Write words to match the expression. 24- ( 6+3)
A dealer sells a certain type of chair and a table for $40. He also sells the same sort of table and a desk for $83 or a chair and a desk for $77. Find the price of a chair, table, and of a desk.
Link Copied!