174k views
0 votes
An even integer can be represented by the expression 2n. Find 3 consecutive even integers that have a sum of 54.

User PDStat
by
8.0k points

1 Answer

6 votes
We generally know consecutive even integer numbers are 2 , 4 , 6, 8, 10 ............

So we can see there is difference of 2 in consecutive even integer.

So if we let first even integer as 2n.

So we will let three consecutive even integer as 2n , 2n+2 , 2n+4

Their sum is 54.

So we can write

2n + 2n + 2 + 2n +4 = 54

6n + 6 = 54

6n = 54- 6

6n = 48

n = (48)/(6) = 8

So n = 8.

So the first number = 2n = 2*8 = 16

second number = 2n+2 = 16+2 = 18

Third number = 2n+4 = 16+ 4 =20

User Stefano Buora
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories