Question

indicate the equation of the given line in standard form show all your work for full creditthe line containing the diagonal ,BD,of a square whose vertices areA(-3,3) B(3,3) C (3,-3) and D (-3,-3)find two equations one for each diagonal

Answer 1

x + y = 0

x - y = 0

Step-by-step explanation:

Given the coordinates:

A(-3,3)

B(3,3)

C(3,-3) and

D (-3,-3)

One diagonal is line AC.

Find the slope of AC:

`m\text{ = }(y2-y1)/(x2-x1)=\text{ }(-3-3)/(3-(-3))=(-6)/(6)=\text{ -1}`

Solpe of AC = -1

Using the slope intercept form, y = mx+b, we have:

y = -1x + b

y = -x + b

The equation for AC:

y = -x

The other diagonal is BD.

find the slope of BD:

`m\text{ = }(y2-y1)/(x2-x1)=\text{ }(-3-3)/(-3-3)=(-6)/(-6)=\text{ 1}`

Slope of BD = 1

The equation of BD:

y = 1x

y = x

Therefore the equation of both lines in standard form will be:

AC ==> x + y = 0

BD ==> x - y = 0