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Help identify BD in terms of TT

Help identify BD in terms of TT-example-1

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arc \ length \ of \ BD = \pi r ( (\angle BPD)/(180) ) \\ \\ \angle BPD=\angle APC=92^o \ \ \text{[vertical angle]} \\ \\ arcBD= \pi *8 *(92)/(180) \approx 4.09 \pi \ in \approx12.85 in

Answer: ≈4.09π in. ≈12.85 in.
User Noah Borg
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