Question

Use the method of completing the square to write the equation of the given parabola in this form:

(y-k)=a(x-h)^2

where a is not equal to 0, (h,k) is the vertex, and x=his the axis of symmetry

Find the x-intercept of the parabola with vertex (1,1) and y-intercept (0,-3). Write your answer in this form: (x1,y1),(x2,y2)

Answer 1

This is a very challenging equation but I'll try my best!

y-k=a(x-h)^2

`Vertex(1,1) ----\ \textgreater \ y-1=a(x-1)^2 contains~ the ~point (0,-3) ----\ \textgreater \ 1-1=a(0-,-3)^2 ----\ \textgreater \ 1=-2a ----\ \textgreater \ a=1/-2 Equation: Y-1=1/-2(x-2)^2`