Question

I'll send a better pic I just need help doing the work and understanding what it's about

Answer 1

The formula to calculate the rate of change is given to be:

`r=(y_2-y_1)/(x_2-x_1)`

In the question, time will be the x-variable while distance will be the y-variable.

QUESTION A: Between 0 and 1.

Between 0 and 1, we will use the following parameters to calculate the rate:

`\begin{gathered} x_1=0 \\ x_2=1 \\ y_1=6 \\ y_2=4 \end{gathered}`

Therefore, the rate is:

`\begin{gathered} r=(4-6)/(1-0)=(-2)/(1) \\ r=-2 \end{gathered}`

The rate is -2.

QUESTION B: Between 1 and 3.

Between 1 and 3, we will use the following parameters to calculate the rate:

`\begin{gathered} x_1=1 \\ x_2=3 \\ y_1=4 \\ y_2=2 \end{gathered}`

Therefore, the rate is:

`\begin{gathered} r=(2-4)/(3-1)=(-2)/(2) \\ r=-1 \end{gathered}`

The rate is -1.

QUESTION C: Between 3 and 6.

Between 3 and 6, we will use the following parameters to calculate the rate:

`\begin{gathered} x_1=3 \\ x_2=6 \\ y_1=2 \\ y_2=3 \end{gathered}`

Therefore, the rate is:

`\begin{gathered} r=(3-2)/(6-3) \\ r=(1)/(3) \end{gathered}`

The rate is 1/3.