92.0k views
4 votes
In how many different ways can a team of 3 boys and 2 girls be formed if there are 4 boys and 5 girls from which to select and Robert (one of the boys) must be on the team?

User Nbz
by
7.9k points

1 Answer

1 vote
The selection of k object out of n, is done is C(n, k) many ways,

where,
C(n, k)= (n!)/(k!(n-k)!)

For example,

the selection of 2 objects out of 3, can be done in:


C(3, 2)= (3!)/(2!1!)= (3*2*1)/(2*1)=3 many ways.

another example,

the selection of 2 objects out of 5 can be done in:


C(5,2)= (5!)/(2!3!)= (5*4*3!)/(2!*3!)= (5*4)/(2)=10

many ways.


back to our example,

there are C(3,2)=3 ways of selecting 2 boys out of 3, to form the 3 boys group together with Robert.

There are C(5,2)=10 many ways to select 2 girls out of 5.

Since any selection of the girls and boys can be combined, we have 3*10=30 different ways of forming the groups.


Answer: 30
User Jameslol
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories