Question

Help me with pre-calculus please, I need to simplify

Answer 1

First, we eliminate the negative exponent by switching the numerator and denominator.

`(3x^4)^-2 = (1)/((3x^4)^2)`
Which then becomes:

`(1)/(9x^8)`
Now we can multiply/combine like terms.

`((x^(4)y^(11) )/(9x^(8)y^(5)) )( (x^(2)y^(5))/(y^2))^2 ( (1)/(9x^8) ) \\ = ((x^(4)y^(11) )/(9x^(8)y^(5)) )( (x^(4)y^(10))/(y^4)) ( (1)/(9x^8) ) \\ = ((x^(8)y^(21) )/(81x^(16)y^(9)) )`
Which then simplifies to:

`(y^(12) )/(81x^(8))`

:)