Question

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Answer 1

`\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^( n)} \qquad \qquad \sqrt[{ m}]{a^( n)}\implies a^{\frac{{ n}}{{ m}}} \\\\\\ |a|\implies \begin{cases} +a\\ -a \end{cases}\implies \pm a\\\\ -------------------------------\\\\ (16x^2)^{(1)/(2)}\implies \pm\sqrt[2]{(16x^2)^1}\implies \pm√(4^2x^2)\implies \pm√((4x)^2)\implies \pm 4x \\\\\\ \begin{cases} +4\\ -4 \end{cases}\implies |4x|`