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If 3x² -6=y for all real numbers x, then x² - 2 =

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3x² - 6 = 3(x² - 2)

If 3(x² - 2) = y, then

(3(x^2-2))/(3)= (y)/(3) \\ \\ x^2-2 = (y)/(3)

Answer:
x² - 2 = y/3
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