Question

JKLM is a rhombus. KM is 6 and JL is 8. Find the perimeter of the rhombus. image of rhombus JKLM with diagonals JL and KM intersecting at point N

Answer 1

If a quadrilateral is a rhombus then:

i) all its sides have equal length,

and

ii) the 2 diagonals are perpendicular and bisect each other.


The 2 diagonals of rhombus JKLM intersect at N.

Then m(MNJ)=90°, |JN|=4 and |NM|=3 units

thus, by the Pythagorean theorem,


`|MJ|= \sqrt{ 3^(2) + 4^(2) }= √(9+16)= √(25)=5`

The perimeter of the rhombus is 4*5 units=20 units.


Answer: 20 units