In the following reaction, what element is made? 241/95Am + 4/2He --> A/Z ? + 1/0n A. 244/97 Bk B. 245/97 Bk C. 244/93 Np D. 245/94 Np

Question

asked Jan 17, 2018 154k views

2 Answers

Shaoyihe · Answer 1 · 2018-01-23T09:55:48+0000

Answer: The correct answer is option (A).

Explanation:

General representation of an element:

A= Atomic mass of the element of X.

Z = Atomic number of the element of X

X = symbol of the element.

$^(241)_(95)Am+^(4)_2He\rightarrow ^(A)_ZX+^(1)_0n$

According to Law of Conservation of Mass:

241+4=A+1

A = 244

Charge is balanced on both the sides:

95+2=Z+0

Z = 97

The element with the atomic number 97 is Berkelium. Hence, the correct answer is option (A).