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In the following reaction, what element is made?

241/95Am + 4/2He --> A/Z ? + 1/0n
A. 244/97 Bk
B. 245/97 Bk
C. 244/93 Np
D. 245/94 Np

In the following reaction, what element is made? 241/95Am + 4/2He --> A/Z ? + 1/0n-example-1
User Clhy
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2 Answers

1 vote
The correct answer is A. 244/97 Bk
User Vinod Makode
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5 votes

Answer: The correct answer is option (A).

Explanation:

General representation of an element:
^(A)_ZX

A= Atomic mass of the element of X.

Z = Atomic number of the element of X

X = symbol of the element.


^(241)_(95)Am+^(4)_2He\rightarrow ^(A)_ZX+^(1)_0n

According to Law of Conservation of Mass:


241+4=A+1

A = 244

Charge is balanced on both the sides:


95+2=Z+0

Z = 97

The element with the atomic number 97 is Berkelium. Hence, the correct answer is option (A).

User Shaoyihe
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