Question

A spinner is divided into many sections of equal size. Some sections are red, some are blue, and the remaining are green. The probability of the arrow landing on a section colored red is 11 over 20. The probability of the arrow landing on a section colored blue is 6 over 20. What is the probability of the arrow landing on a green-colored section?

Answer 1

I just added the 11 and 6 and got 17 so 17 subtract 20 is 3 there are only 3 spaces left. simple ;)

Answer 2

red = 11/20....this tells me that there are 11 red ones and 20 total sections
blue = 6/20...this tells me there is 6 blue ones and 20 total sections

so if the rest are green, and if there are 20 total spaces and 11 are red and 6 are blue....that leaves (20 - 11 - 6) = 3...so 3 are green.

so the probability of picking a green one is 3/20 <==