Question

The center of a circle is located at c(3,-13). the x-axis is tangent to the circle at (3,0). find the equation of the circle.

Answer 1

hello :
let : A(3,0)
the ridus is : CA = √((3-3)² +(0+13)²) = 13
he equation of the circleis : (x-3)² + (y+13)² = 169