205k views
4 votes
Use the normal distribution of fish lengths for which the mean is 11 inches and the standard deviation is 2 inches. assume the variable x is normally distributed. left parenthesis a right parenthesis what percent of the fish are longer than 12 ?inches

User Alex Riina
by
8.4k points

1 Answer

3 votes

To solve this problem, we make use of the z statistic. What we have to do here is to find for the z score using the given data and from the standard probability tables for z, we locate the proportion of the fish longer than 12 inches.

The formula for calculating the z score is:

z = (x – μ) / σ

where,

x = the sample value = 12 inches

μ = the sample mean = 11 inches

σ = 2 inches

so,

z = (12 – 11) / 2

z = 1 / 2

z = 0.5

Since we are looking for the values greater than 12, so this is a right tailed test. Using the tables, the value of p at this value of z is:

p (z = 0.5) = 0.3085

Therefore there is a 30.85% probability that the fish is longer than 12 inches.

User Will Larche
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories