we have the equation
Remember that
The curve is symmetric about the polar axis if for every point (r,θ) on the graph, the point
(r,−θ) is also on the graph
we have that
sin(θ) is not equal to sin(-θ)
so
Is not symmetric about the polar axis
The curve is symmetric about the pole if, for every point (r,θ) on the graph, the point (r,π+θ) is also on the graph
so
sin(θ) is the same that sin(θ+π)
therefore
The curve is symmetric about the pole
using a graphing tool
see the attached figure