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3+-1/1/3 the first half is 3+-1 the second half is 1/3

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\bf \cfrac{3\pm1}{(1)/(3)}\implies \begin{cases} \cfrac{3+1}{(1)/(3)}\\\\ \cfrac{3-1}{(1)/(3)} \end{cases}\\\\ -------------------------------\\\\


\bf \cfrac{3+1}{(1)/(3)}\implies \cfrac{4}{(1)/(3)}\implies \cfrac{(4)/(1)}{(1)/(3)}\implies \cfrac{4}{1}\cdot \cfrac{3}{1}\implies \cfrac{4\cdot 3}{1\cdot 1}\implies \cfrac{12}{1}\implies \boxed{12} \\\\\\ \cfrac{3-1}{(1)/(3)}\implies \cfrac{2}{(1)/(3)}\implies \cfrac{(2)/(1)}{(1)/(3)}\implies \cfrac{2}{1}\cdot \cfrac{3}{1}\implies \cfrac{2\cdot 3}{1\cdot 1}\implies \cfrac{6}{1}\implies \boxed{6}
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