What must be added to 3x-7 to make x^2+4x-1

asked Dec 18, 2018 143k views

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The term that can be added is the difference between the two expressions you have:

x^2+4x-1-(3x-7)

x^2+4x-1-3x+7

x^2+x+6

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4 votes

3x-7+c=x^2+4x-1
find c
minus 3x from both sides
-7+c=x^2+x-1
add 7 to both sides
c=x^2+x+6

x^2+x+6 must be added

Stradivariuz answered Dec 24, 2018

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