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The axis of symmetry for the graph of the function is f(x) =1/4 x^2 + bx + 10 is x = 6. What is the value of b?

The axis of symmetry for the graph of the function is f(x) =1/4 x^2 + bx + 10 is x = 6. What is the value of b?
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The axis of symmetry for the graph of the function is f(x) =1/4 x^2 + bx + 10 is x = 6. What is the value of b?

User TomDunning
by
7.8k points

2 Answers

3 votes

Answer: -3

Step-by-step explanation: trust me

User Ravinsp
by
7.8k points
1 vote
AOS = -b/2a
6 = -b/(2/4)
-b = 3
b = -3
User Almulo
by
8.2k points
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