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General form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)

User Techdude
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1 Answer

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hello :
an equation of the circle Center at the A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a = -2 and b = 1 (Center at the A(-2,1))
r = AP......P( -4 , 1)
r² = (AP)²
r² = (4+2)² +(1-1)² = 36
an equation of the circle that satisfies the stated conditions.
Center at
A(-2,1), passing through P(-4, 1) is : (x+2)² +(y-1)² = 36

User Omar Bahareth
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