Answer:
the zeros are x = 0, x = -1, x = -7
choices B, C and E
Explanation:
The given polynomial is
f(x) = x²(x+1)(x-7)
To find the zeros of this polynomial set f(x) = 0 and solve for x
We get
f(x) = 0
==> x²(x+1)(x-7) = 0
This means either x² = 0, (x+1) = 0, (x-7) = 0
x² = 0 ==> x = 0
(x+1) = 0 ==> x = - 1
(x-7) = 0 ==> x = 7
So the zeros are x = 0, x = -1, x = 7