Question

What are the zeros of the polynomial f(x)=x2(x+1)(x−7)? Select THREE that apply.

A.–7 B.–1 C. 0 D. 1 E. 7

Answer 1

the zeros are x = 0, x = -1, x = -7

choices B, C and E

Explanation:

The given polynomial is
f(x) = x²(x+1)(x-7)

To find the zeros of this polynomial set f(x) = 0 and solve for x

We get

f(x) = 0

==> x²(x+1)(x-7) = 0

This means either x² = 0, (x+1) = 0, (x-7) = 0

x² = 0 ==> x = 0

(x+1) = 0 ==> x = - 1

(x-7) = 0 ==> x = 7

So the zeros are x = 0, x = -1, x = 7