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3 votes
1. Space
2. ∅
3. ↔
LM

4. plane p
5. None of these

1. Space 2. ∅ 3. ↔ LM 4. plane p 5. None of these-example-1
1. Space 2. ∅ 3. ↔ LM 4. plane p 5. None of these-example-1
1. Space 2. ∅ 3. ↔ LM 4. plane p 5. None of these-example-2
User OliverQ
by
7.8k points

1 Answer

4 votes
De Morgan's law: (A∩B)' = A'∪B'

(S₁∩P)' = S'₁ ∪ P'

S'₁={P} ∪ {S₂}
P' ={ S₁} ∪ {S₂}

S'₁ ∪ P' ={P} ∪ {S₂} ∪ { S₁} ∪ {S₂}

(S₁∩P)' = S'₁ ∪ P' = SPACE

User Stan Reduta
by
8.5k points
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