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If z is a standard normal variable, find the probability. the probability that z lies between -2.41 and 0

User ChiYoung
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1 Answer

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To solve this problem, what we can do first is to find for the value of probability (p value) using the standard distribution tables for z. Looking at the table, we can see that the p values are:

when z = - 2.41:

p value = P (z = - 2.41) = 0.0080

when z = 0:

p value = P (z = 0) = 0.5000

The probability that z lies between – 2.41 and 0 is the difference of the two probabilities, with the bigger probability subtracted by the smaller probability. That is:

P (0 ≥ z ≥ -2.41) = 0.5000 - 0.0080

P (0 ≥ z ≥ -2.41) = 0.4920

User Akrun
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