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Factor with work shown
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Apr 21, 2018
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Factor with work shown
Mathematics
high-school
Heartbit
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1
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4
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group and factor
trial and error
ok, so we group
(x⁵+x³)+(x²+1)
factor out gcf from each
x³(x²+1)+(x²+1)
undistribute
(x²+1)(x³+1)
factor sum of 2 perfect cubes
remember that a³+b³=(a+b)(a²-ab+b²)
so
(x²+1)(x+1)(x²-x+1) is factored form
Jagruttam Panchal
answered
Apr 26, 2018
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Jagruttam Panchal
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