Original Function:
![\sf\sqrt[\sf 3]{\sf x}](https://img.qammunity.org/2018/formulas/mathematics/high-school/q1fodqel5ks9tqdhh91a14nclg8jruq30g.png)
If you add something inside the square root, it will shift the graph of the function to the left that same amount of units.
Example:
![\sf\sqrt[\sf 3]{\sf x+4}](https://img.qammunity.org/2018/formulas/mathematics/high-school/9l9q5q112rd5xfnr87xl7beu1no3xpamrz.png)
Shifts the original function to the left 4 units.
If you subtract something inside the square root, it will shift the graph of the function to the right that same amount of units.
Example:
![\sf\sqrt[\sf 3]{\sf x-6}](https://img.qammunity.org/2018/formulas/mathematics/high-school/yk69ub6zg9ix3udsegxpula54zwddgtoo2.png)
Shifts the original function to the right 6 units.
If you add something outside of the square root, it will shift the graph of the function up that same amount of units.
Example:
![\sf\sqrt[\sf 3]{\sf x}+3](https://img.qammunity.org/2018/formulas/mathematics/high-school/pfdmxg4lh46qqfrqq69xvs11e091eyetvv.png)
Shifts the original function up 3 units.
If you subtract something outside of the square root, it will shift the graph of the function down that same amount of units.
Example:
![\sf\sqrt[\sf 3]{\sf x}-2](https://img.qammunity.org/2018/formulas/mathematics/high-school/3ousrxgogqir06bjoj0duqj6tbld50f95p.png)
Shifts the original function down 2 units.
So in the case of
![\sf\sqrt[\sf 3]{\sf x+6}-8](https://img.qammunity.org/2018/formulas/mathematics/high-school/vbfbh2r62u598tyoihk5oj9fi1ul50dfnd.png)
, it will shift the original function 6 units to the left and 8 units down.
The domain is the x-values. The x-values of the original function is all real numbers. Shifting the graph down and to the left would not change the domain.
The range is the y-values. The y-values of the original function is all real numbers. Shifting the graph down and to the left would not change the domain.
So your answer is
C.