Question

A teacher gave her class two exams; 60% of the class passed the second exam, but only 48% of the class passed both exams. What percent of those who passed the second exam also passed the first exam?

Answer 1

should be
0.48 / 0.60 = 0.80 = 80%

answer
80% passed the second exam also passed the first exam

Answer 2

Percent of those who passed the second exam also passed the first exam = 80 %

Explanation:

Let the number of students be 100.

We have 60% of the class passed the second exam

Number of students passed the second exam
`=(60)/(100)* 100=60`

We also have

Only 48% of the class passed both exams

Number of students passed both exams
`=(4)/(8100)* 100=48`

Percent of those who passed the second exam also passed the first exam
`=(48)/(60)* 100=80 \%`