we have the sequence
16, 48, 80, ..
so
a1=16 ------> first term
a2=48 -----> second term
a3=80 ----> third term
step 1
Find the common difference d
a2-a1=48-16=32
a3-a2=80-48=32
so
the value of d=32
step 2
Find the explicit formula
f(n)=f(1)+(n-1)d
we have
f(1)=16
d=32
substitute
f(n)=16+(n-1)*32
Simplify
f(n)=16+32n-32
f(n)=32n-16
step 3
Find the distance traveled in the 5th second
so For n=5
substitute in the formula
f(5)=32*5-16
f(5)=144 feet