a) The free-body diagram of the given situation is shown below:
where you can notice that the vector for the tension is larger than the vector for the weight of the block, due to the block is going up. That is, the force T, in magnitude is greater than F.
b) The weight of the block is:
F = m·g = (750 kg)(9.8 m/s²)
F = 7,350 N
c) The net force is:
Fn = m·a
Fn = (750 kg)(2.5 m/s²)
Fn = 1,875 N
d) The tension force is:
T - F = m·a
T = m·a + F
T = 1,875N + 7,350N
T = 9,225N