IM NOT SURE IF THIS IS THE ANSWER
sin x=12/13=O/H
O=12, H=13
A=√(H^2-O^2)=√(13^2-12^2)=√(169-144)=√25=5
cos x=A/H=-5/13
tan x=O/A=-12/5
csc x=13/12
sec x=-13/5
cot x=-5/12if sin theta=12/13 and tan <0, find the exact values of the remaining trigonometric functions of theta.
use x for theta
O for opposite side
A for adjacent side
H for hypotenuse
if sin theta=12/13 and tan <0, reference angle must be in quadrant II