Question

Find the rectangular coordinates of the point with the polar coordinates (8, 3 divided by 2 pi).

Answer 1

(r, theta)= (8, 3/2 pi)
r=(x^2 +y^2)^(1/2)
theta= 3/2 pi
x= r(costheta)
y=r(sintheta)
x=8(cos(3/2 pi))
y=8(sin(3/2 pi))
x=8(0)
y=8(-1)
x=0
y=-8
r=((-8)^2+(0)^2)^(1/2)
r=(64+0)^(1/2)
r=8
rectangular coordinates= (0,-8)