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Ray MO bisects LMN LMO = 6x-20 and NMO =2x+36. solve for x and find LMN

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3 votes
6x - 20 = 2x + 36
6x - 2x = 36 + 20
4x = 56
x = 56/4
x = 14

m∠LMN = 6x - 20 + 2x + 36 = 8x + 16 = 8 * 14 + 16 = 128°
Ray MO bisects LMN LMO = 6x-20 and NMO =2x+36. solve for x and find LMN-example-1
User David Bukera
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8.4k points
4 votes

Answer: The required value of x is 14 and the maesure of angle LMN is 128 degrees.

Step-by-step explanation: As given in the question and shown in the attached figure below, ray MO bisects angle LMN.

Also,


m\angle LMO=6x-20,\\\\m\angle NMO=2x+36.

We are to find the value of x and the measure of angle LMN.

Since ray MO bisects angle LMN, so we must have


m\angle LMO=m\angle NMO\\\\\Rightarrow 6x-20=2x+36\\\\\Rightarrow 6x-2x=36+20\\\\\Rightarrow 4x=56\\\\\Rightarrow x=(56)/(4)\\\\\Rightarrow x=14.

And, we get


m\angle LMN=6x-20+2x+36=8x+16=8*14+16=112+16=128.

Thus, the required value of x is 14 and the maesure of angle LMN is 128 degrees.

Ray MO bisects LMN LMO = 6x-20 and NMO =2x+36. solve for x and find LMN-example-1
User Arabia
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8.0k points