15 Points!!! NEED ASAP!!!! Given an exponential function for compounding interest, A(x) = P(1.04)x, what is the rate of change?

asked May 24, 2018 150k views

4 votes

15 Points!!! NEED ASAP!!!!

Given an exponential function for compounding interest, A(x) = P(1.04)x, what is the rate of change?

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2 votes

A(x) = P(1.02)^x
A(x) = P(1 + 0.02)^x
A(x) = P(1 + r)^x

Therefore rate of change = 0.02 = 2%

TinaW answered May 30, 2018

by TinaW

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