Question

A gas sample contains 4.00 g of ch4. what is the volume of the sample at stp

Answer 1

Hey there !

Molar mass CH4 = 16.04 g/mol

16.04 g ------------------ 22.4 L ( at STP )
4.00 g ------------------- Volume

Volume = 4.00 * 22.4 / 16.04

Volume = 89.6 / 16.04

Volume = 5.586 L

Answer 2

Answer : The volume of the gas sample at STP is, 5.6 L

Explanation : Given,

Mass of
`CH_4` = 4 g

Molar mass of
`CH_4` = 16 g/mole

First we have to calculate the mole of
`CH_4`

`\text{Moles of }CH_4=\frac{\text{Mass of }CH_4}{\text{Molar mass of }CH_4}=(4g)/(16g/mole)=0.25mole`

Now we have to calculate the volume of
`CH_4` at STP.

As we know that at STP, 1 mole of gas contains 22.4 L volume of gas

As, 1 mole of gas contains 22.4 L volume of gas sample

So, 0.25 mole of gas contains
`0.25* 22.4L=5.6L` volume of gas sample

Therefore, the volume of the gas sample at STP is, 5.6 L