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EMERGENCY PLS HELP: A person invested $420 in an account growing at a rate allowing the money to double every 7 years. How much money would be in the account after 16 years, to the nearest dollar?

User Zrg
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2 Answers

9 votes

Final answer:

To calculate the growth of a $420 investment that doubles every 7 years after 16 years, find the full doubling periods and the growth for the remaining time, which leads to approximately $2094 in the account after 16 years.

Step-by-step explanation:

Calculation of Investment Growth

The amount of money in an account after a certain number of years can be calculated using the formula for compound interest. As the money doubles every 7 years, this represents an exponential growth according to the rule of 72. To find the total after 16 years, we divide 16 by 7 to calculate the number of full doubling periods, which in this case is about 2.29 periods. Since the investment is not exactly at a doubling point at the 16-year mark, we can use the power of compounding to estimate the final amount.


For the first 14 years (or two doubling periods), the $420 investment will double twice:

After 7 years: $420 × 2 = $840

After 14 years: $840 × 2 = $1680

For the remaining 2 years, we need to find the growth factor for a 7-year period (which is 2) and then raise it to the fraction of time (2/7 years) that we're interested in. This can be represented as:

$1680 × 2^(2/7) = $1680 × approximately 1.246 = $2094

Rounding this to the nearest dollar, we have $$2094 in the account after 16 years.

User Mussnoon
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6 votes

Answer:

2048

Step-by-step explanation:

a=420

d=7-- d is the doubling time

t=16

plug in y =420(2) 16/7

y=2047.94293906

y≈2048

User KotoroShinoto
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