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Given that n=a3b4c5 where a, b and c are distinct prime numbers, what is the smallest number with which n should be multiplied such that it becomes a perfect square, a perfect cube as well as a perfect
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Given that n=a3b4c5 where a, b and c are distinct prime numbers, what is the smallest number with which n should be multiplied such that it becomes a perfect square, a perfect cube as well as a perfect fifth power?

User Kelechi
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1 Answer

1 vote
a^27b^26c^25 would be the smallest number.
This yields a^30b^30c^30.
User Fasani
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8.0k points
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