Question

There are 36 cans of green beans and 48 cans of corn. Then display designer wants an equal amount of each vegetable in each row what is the greatest number of cans of corn that can be in each row

Answer 1

What is the largest factor for both numbers?
12.
Then 36/12 = 3 and 48/12 = 4
There are 3 cans of green beans and 4 cans of corn in each row.

Answer 2

I would look at the common factors for this one. so let's factor them
36 = 2 * 18
36 = 3 * 12
36 = 4 * 9

48 = 2 * 24
48 = 3 * 16
48 = 4 * 12
48 = 6 * 8

if we look the greatest common factor they have would be 12. But if they both had 12 then corn would oy have 4 in each row. But if we do the smallest amount of rows then we would have more cans as the owner wants. So if we madeniy 2 rows then corn would have 24 in each row. that wpuld.be the most possible