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Find all complex solutions of 5x^2-6x+2=0.

(If there is more than one solution, separate them with commas.)

User WiatroBosy
by
8.1k points

1 Answer

3 votes
we use quadratic formula for that one
remember that √-1=i

so

for
ax^2+bx+c=0

x=(-b+/-√(b^2-4ac))/(2a)
so
given
5x^2-6x+2=0
a=5
b=-6
c=2


x=(-(-6)+/-√((-6)^2-4(5)(2)))/(2(5))

x=(6+/-√(36-40))/(10)

x=(6+/-√(-4))/(10)

x=(6+/-2i)/(10)


x=(3)/(5)+(i)/(5), (3)/(5)-(i)/(5)
User Stem Florin
by
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