Question

Calculate the pH given [OH-] = 1.25 x 10^-8

Answer 1

The pH is 6.1.

Step-by-step explanation:

1st) With the concentration of OH-, we have to calculate the pOH:

`\begin{gathered} pOH=-log\lbrack OH^-\rbrack \\ pOH=-log(1.25*10^(-8)) \\ pOH=7.9 \end{gathered}`

2nd) Using the relation between pH and pOH, we can calculate the pH:

`\begin{gathered} pH+pOH=14 \\ pH+7.9=14 \\ pH=14-7.9 \\ pH=6.1 \end{gathered}`

So, the pH is 6.1.