I am somehow confused with the given matrix. Because usually, when the system of equations is given as:
ax + by = c
dx + ey = f
the matrix would be written in this manner:
![\left[\begin{array}{ccc}a&b&c\\d&e&f\end{array}\right]](https://img.qammunity.org/2018/formulas/mathematics/high-school/fkzoxuy5acxvlqd4dbrwidop4ivbo0bvxf.png)
Let me just assume that the arrangement of the given corresponds to this system of equations:
4x + 8y = 0
2x + 5y = 6
So you write it as
![\left[\begin{array}{ccc}4&8&0\\2&5&6\end{array}\right]](https://img.qammunity.org/2018/formulas/mathematics/high-school/h29tujb0ltxb7fdbx6btxf6rzdnui5bn44.png)
In order to solve this, the matrix should look like this where x and y are the answers
![\left[\begin{array}{ccc}1&0&x\\0&1&y\end{array}\right]](https://img.qammunity.org/2018/formulas/mathematics/high-school/xrqkifl2x63jag36kt93h8iuvvr58dwtj8.png)
So, the first thing to do is apply this pattern: Row 2 = Row 1 - 2*Row 2. The result will be
![\left[\begin{array}{ccc}4&8&0\\0&-2&-12\end{array}\right]](https://img.qammunity.org/2018/formulas/mathematics/high-school/kujrc64bowmxoggdy7ao3n9lw2ehewi5le.png)
Next, Row 1 = (Row 1/4) + R2:
![\left[\begin{array}{ccc}1&0&-12\\0&-2&-12\end{array}\right]](https://img.qammunity.org/2018/formulas/mathematics/high-school/nj5u9tipzov94woog99szajpugog5wajr4.png)
Lastly, Row 2 = Row 2 / -2:
Thus, the answer is x=-12 and y=6.