Question

Find the quotient of the quantity 4 times x to the 3rd power times y plus 12 times x to the 2nd power times y to the 3rd power minus 20 times x times y all over 4 times x times y. x2 + 3xy2 + 5

x2 + 3xy − 5
4x3y + 12x2y3 − 5
x2 + 3xy2 − 5

Answer 1

The quotient is:

`x^2+3xy^2-5`

Explanation:

We have to find the quotient of the algebraic quantity:

`(4x^3y+12x^2y^3-20xy)/(4xy)`

i..e we have dividend as:

`4x^3y+12x^2y^3-20xy` , divisor as:
`4xy`

Now we can write our dividend term as:

`4x^3y+12x^2y^3-20xy=4xy(x^2+3xy^2-5)`

Hence, the we can represent our expression as:

`(4x^3y+12xy^3-20xy)/(4xy)=(4xy(x^2+3xy^2-5))/(4xy)\\\\=x^2+3xy^2-5`

Hence, the quotient is:

`x^2+3xy^2-5`

Answer 2

We have to find the quotient :
( 4 x³ y + 12 x² y³ - 20 x y ) / ( 4 x y ) =
= 4 x y ( x² + 3 x y² - 5 ) / ( 4 x y ) = ( Then 4 x y will be cancelled )
= x² + 3 x y² - 5
Answer:
D ) x² + 3 x y² - 5